(5x-2)=(3x^2+4)

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Solution for (5x-2)=(3x^2+4) equation: 



(5x-2)=(3x^2+4)

We move all terms to the left:

(5x-2)-((3x^2+4))=0

We get rid of parentheses

5x-((3x^2+4))-2=0



We calculate terms in parentheses: -((3x^2+4)), so:

(3x^2+4)

We get rid of parentheses

3x^2+4

Back to the equation:

-(3x^2+4)



We get rid of parentheses

-3x^2+5x-4-2=0

We add all the numbers together, and all the variables

-3x^2+5x-6=0

a = -3; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·(-3)·(-6)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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